Find yhe sum of all number from 10 to 50 excluding the number which divisible by 8
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the number divisible by 8 in 10 to 50 is
16 , 24 , 32 , 40, 48
16+24+32+40+48=160
16 , 24 , 32 , 40, 48
16+24+32+40+48=160
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Heya !! Here Is Ur Ans :=>>>
= ( Numbers From 10 to 50 - Numbers divisible by 8 )
= (10 + 11 + 12 + 13 + 14 _ _ _ _ _ _ 50) - ( 16 + 24 + 32 + 40 + 48 )
:· This Is In The form of AP so, Applying in an = a+ (n-1) x d
= 30 x 41 - 32 x 5
= 1070
I Hope This Helps U :-)
= ( Numbers From 10 to 50 - Numbers divisible by 8 )
= (10 + 11 + 12 + 13 + 14 _ _ _ _ _ _ 50) - ( 16 + 24 + 32 + 40 + 48 )
:· This Is In The form of AP so, Applying in an = a+ (n-1) x d
= 30 x 41 - 32 x 5
= 1070
I Hope This Helps U :-)
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