Question

find your consecutive term in an AP whose sum is 36 and the product of the 2nd and 4th is 105. The terms are in ascending order​

Answer 1

Step-by-step explanation:

S

4

=36

⇒

2

4

[2a+(4−1)d]=36

⇒2a+3d=18⟶(1)

A/Q,a

2

.a

3

=a

1

.a

4

+8

⇒(a+d)(a+2d)=a.(a+3d)+8

⇒d

2

=4

⇒d=±2

If d=2 then a=6

then the four terms is 6,8,10,12

If d=−2 then a=12

then the four terms is 12,10,8,6