find z by using determinant method X + 2y = -3z +6 ,2x + z = 7 - 4y , 9z + 2y = 14 -3x
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let the value of x,y,z is z.
x+2y+2x+z+9z+2y = -3z+6+7-4y+14-3x
3x+4y+10z = -3z+27-4y-3x
3x+3x+4y+4y+10z+3z = 27
6x+8y+13z = 27
let the value of x,y and z be z.
6z+8z+13z = 27
27z = 27
z = 1
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