Question

Find zeoes of cubic polynomial p(x)= x3+x2+x+1

Answer 1

Explanation:

x^3+x^2+x+1=0

One of the zeroes will be a factor of the constant term that is 1

Factors of 1 are= 1,-1

Then,

p(-1)=(-1)^3+(-1)^2+(-1)+1=0

      = -1+1-1+1=0

      = 0=0

Therefore one of the zero is -1

x=-1

x+1=0

Using long division method we get,

x^3+x^2+x+1=(x^2+1)(x+1)

 Then,

The zeroes are -1, √-1, -√-1

Answer 2

Answer:

P ( 0 ) = x3 + x2 + x + 1

P (0) = 0 +0+0 +1

P (0) = 1

This is the answer

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Explanation: