Question

Find zero : 3x² + x-2​

Answer 1

Solution :-

→ 3x² + x - 2 = 0

→ 3x² + 3x - 2x - 2 = 0

→ 3x ( x + 1 ) - 2 ( x + 1 ) = 0

→ ( 3x - 2 ) ( x + 1 ) = 0

Taking ( 3x - 2 ) = 0

→ 3x = 2

→ x = 2/3

Taking ( x + 1) = 0

→ x = - 1

Zeroes of polynomial are 2/3 and - 1

Answer 2

Answer:

First middle term splitting

3x2+3x-2x-2

Then,

3x(x+1)-2(x+1). (x+1)=0

(3x-2) (x+1). x= -1

3x+2=0

3x= -2

x= -2/3..

Step-by-step explanation:

-1 & -2/3 are the zeroes........

............thanks