Question

(find zero and varify relationship between the zero and cofficients
4S²-4S+1​

Answer 1

Answer:

retaegerger

Step-by-step explanation:

egrawegraegre

Answer 2

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$correct \: question\:is$

find zero and verify relationship between the zero and coefficients

4S²-4S+1​

4s² - 4s+1 = 0

⇒4s²-2s-2s+1 = 0

⇒2s(2s-1)-1(2s-1) = 0

⇒(2s-1) (2s-1) = 0

⇒2s - 1  = 0 ; 2s - 1= 0

⇒s = 1/2, 1/2

sum of the zeroes = 1/2 + 1/2  = -(co-efficient of s)  /(co-efficient of s²)

                             =2/2 = 4/4

                             = 1=1

product of the zeroes = 1/2(1/2)  = constant term / coefficient of s²

                                    = 1/4= 1/4