Question

find zero of 2x²-3+5x​

Answer 1

Step-by-step explanation:

First of all split the middle term and it will be in this form

2x^2+6x-x-3

take common

2x(x+3)-1(x+3)

(2x-1)(x+3)

x=1/2 , -3

verification

let alpha and beta be the zeroes of the polynomial

alpha=1/2 and beta=-3

alpha+beta=-b/a

=>1/2+(-3)=-5/2

=>-6+1/2=-5/2

=>-5/2=RHS

and aplha×beta=c/a

=>1/2×-3=-3/2

=>-3/2= RHS

hence, verified

Answer 2

Given:-

P(x)=0

→2x²+5x-3=0

$\rule{200}{1}$

To Find:-

→The Zeros of p(x)?

$\rule{200}{1}$

Answer:-

→2x²+5x-3=0[Standard Form]

๛S=5[Sum of Equation]

๛P=-6[Product of Equation]

๛6×-1=-6

๛6-1=5

★Since There is Common Factors, We will do Spiliting the middle term★

→2x²+6x-x-3=0

→2x(x+3)-1(x+3)=0

→2x-1=0

→x+3=0

$\rule{200}{1}$

•Taking 2x-1=0

→2x-1=0

→2x=1

→x=$\frac{1}{2}$

$\rule{200}{1}$

•Taking x+3=0

→x+3=0

→x=-3

$\rule{200}{2}$