Question

Find zero of 3x² - 26x + 8

Answer 1

Step-by-step explanation:

3x² -26x +8

than,

by using quadratic equation formula:

a = 3

b= -26

c= 8

so,

using fomula =( -b +- √b² - 4ac ) / 2a

Than,

{- ( -26) +- √ (-26)² - 4*3*8} / 2* 3

{ 26 +- √ 676 - 96 } / 6

{ 26 +- √ 580 } /6

( 26 +- 24 ) / 6

Now,

Taking + ve sign,

(26 + 24 ) /6 = 25 /3

Taking - ve sign,

( 26 - 24) / 6 = 1 /3

Answer 2

3x² - 26x + 8=0

Comparing the given polynomial with ax²+bx+c =0, we get

a=3, b= -26 and c=8

D= b²-4ac

=(-26)²-4(3)(8)

= 676 -96

= 580

Here, D>0

Therefore, the given quadratic equation has two distinct real roots.

Using quadratic formula,

$x = \frac{ - b ± \sqrt{D} }{2a} \\ x = \frac{26 ± \sqrt{580} }{2 \times 3} \\ x = \frac{26 ±2 \sqrt{145} }{6} \\x = \frac{13 ± \sqrt{145} }{3} \\ x = \frac{13 + \sqrt{145} }{3} , \frac{13 - \sqrt{145} }{3}$