Question

find zero of 5x^2-14x+8
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Solution:-

Factoring 5x2-14x+8

The first term is, 5x2 its coefficient is 5 .

The middle term is, -14x its coefficient is -14 .

The last term, "the constant", is +8

Step-1 : Multiply the coefficient of the first term by the constant 5 • 8 = 40

Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -14 .

-40 + -1 = -41

-20 + -2 = -22

-10 + -4 = -14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -4

5x2 - 10x - 4x - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

5x • (x-2)

Add up the last 2 terms, pulling out common factors :

4 • (x-2)

Step-5 : Add up the four terms of step 4 :

(5x-4) • (x-2)

Which is the desired factorization

(x - 2) • (5x - 4) = 0.