find zero of 5x^2-14x+8
Answers
Step-by-step explanation:
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Answer:
Solution:-
Factoring 5x2-14x+8
The first term is, 5x2 its coefficient is 5 .
The middle term is, -14x its coefficient is -14 .
The last term, "the constant", is +8
Step-1 : Multiply the coefficient of the first term by the constant 5 • 8 = 40
Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -14 .
-40 + -1 = -41
-20 + -2 = -22
-10 + -4 = -14 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -4
5x2 - 10x - 4x - 8
Step-4 : Add up the first 2 terms, pulling out like factors :
5x • (x-2)
Add up the last 2 terms, pulling out common factors :
4 • (x-2)
Step-5 : Add up the four terms of step 4 :
(5x-4) • (x-2)
Which is the desired factorization
(x - 2) • (5x - 4) = 0.