Question

Find Zero of given polynomial P(x)= y²-√3​

Answer 1

Here, p(x)=3x−2.

In order to find zero of p(x), we equate p(x) to 0,

i.e p(x)=0.

$⇒3x−2=0⇒3x=2⇒x= \frac{2}{3}$

$\texttt ∴ \frac{2}{3} \: is \: the \: zero \: of \: \: p(x).$

Answer 2

Answer:

Here, p(x)=3x−2.

In order to find zero of p(x), we equate p(x) to 0,

i.e p(x)=0.

⇒3x−2=0⇒3x=2⇒x= \frac{2}{3}⇒3x−2=0⇒3x=2⇒x=

3

2

\texttt ∴ \frac{2}{3} \: is \: the \: zero \: of \: \: p(x).∴

⅔ is the zero of p(x).