Question

find zero of p(x)=(x-2)^2+4
no scam please

Answer 1

Answer:

Given polynomial,

p(x)=(x-2)²-(x+2)²

(x-2)²-(x+2)²=0

[a²-b²=(a-b)(a+b)]

(x-2-(x+2))(x-2+x+2)=0

(x-2-x-2)(2x)=0

(-4)(2x)=0

2x=0/-4

2x=0

x=0/2

x=0

Therefore,zero of the polynomial is 0.

Hope it helps

Answer 2

Answer:

Zeroes of P(x) is 0