find zero of p(X) = (x-2)^2 - (x-3)^2
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raviprakashtiwari47
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Hey friend ☺
Here is your answer
p(x)=x(x+2)(x-3)
x=0
x+2=0
x=-2
x-3=0
x=3
ZEROES OF THE POLYNOMIAL ARE :
0, -2 and 3
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