Question

find zero of p(x) = x²-3x+2​

Answer 1

$= {x}^{2} - 3x + 2 \\ = {x}^{2} - 2x - x + 2 \\ = x(x - 2) - 1(x - 2) \\ = (x - 2)(x - 1)$

Therefore,

Zeroes of p(x) are 1 and 2

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Answer 2

Step-by-step explanation:

P(x)=x2−3x+2

Put p(x)=0, For finding zeroes of the given polynomial 

⟹x2−3x+2=0

⟹x2−x−2x+2=0

⟹x(x−1)−2(x−1)=0

⟹(x−2),(x−1)=0

⟹x−2=0 ,    x−1=0

⟹x=2 ,          x=1

⟹2,1 are zeroes of the equation p(x)=x2−3x+2.