Question

find zero of polynomial 6x²-3-7x​

Answer 1

Answer:

$6 {x}^{2} - 7x - 3 \\ = 6 {x}^{2} - 9x + 2x - 3 \\ = 3x(2x - 3) + 1(2x - 3) \\ (2x - 3)(3x + 1) \\ so \: zeroes \: are \: \frac{3}{2} and \: \frac{ - 1}{3}$