find zero of polynomial
p(x)= 5u²+10u²
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Answered by
2
Hey There
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P ( x ) = 0 [ Since Zeroes of polynomial ]
→ 5u² + 10u ² =0
→ 15u² =0
→ u² = 0
→ u = 0 , 0
Hence the zeroes are - 0 and 0
Hope this may help you
___________________________________________
P ( x ) = 0 [ Since Zeroes of polynomial ]
→ 5u² + 10u ² =0
→ 15u² =0
→ u² = 0
→ u = 0 , 0
Hence the zeroes are - 0 and 0
Hope this may help you
TheAishtonsageAlvie:
:D
Hey sorry to say but zero can't be negative..
so where i put ?
thats dash not negative sign
In last line u wrote -0 and 0
nope thats dash not negative sign
ohh sryy bro its my fault I think its negative sign..
:D NP , keep collaborating
Hey why have u deleted my answers. He has asked wrong question and I'm just suggesting him.U tell me..... sin squared theta + cot squared theta = 1 ???? Or usne jo proof kiya h na wo bhi dekh lo yahi proof kiya h
Answered by
2
Given: p(x) = 5u^2+10u^2
=>p(x) = 15u^2 (15u square okk)
Now,there's only one choice.
You can put only 0(zero) in place of u.
Hence, 0(zero) is only the answer.
=>p(x) = 15u^2 (15u square okk)
Now,there's only one choice.
You can put only 0(zero) in place of u.
Hence, 0(zero) is only the answer.
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