Question

find zero of polynomial p(X)=x^2-4x+5​

Answer 1

${x}^{2} - 4x + 5 = 0 \\ {x}^{2} + ( - 5 + 1)x + 5 = 0 \\ {x}^{2} - 5x + x + 5 = 0 \\ x(x - 5) + 1(x + 5) = 0$

friend there can't be any zero because as you can see these are not equal.

Sorry, if I am wrong, but according to me there should be -5 in question not +5.