Question

Find zero of polynomial p(x)= (x-4)²-(x-6)²

Answer 1

Hi ,

It is given that ,

p( x ) = ( x - 4 )² - ( x - 6 )²

To find zero of p( x ) , we have to

take p( x ) = 0 , we get

( x - 4 )² - ( x - 6 )² = 0

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We know the algebraic identity,

a² - b² = ( a + b )( a - b )

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[ ( x - 4 )+(x-6) ][ ( x - 4 )- ( x - 6 ) ] = 0

( x - 4 + x - 6 )( x - 4 - x + 6 ) = 0

( 2x - 10) ( 2 ) = 0

2x - 10 = 0

2x = 10

x = 10/2

x = 5

Therefore ,
.
Zero of p( x ) is 5

I hope this helps you.
: )

Answer 2

Hiii friend,

(X-4)² - (X-6)²

=> (X)² + (4)² - 2 × X × 4 -(X² + (6)² - 2 × X × 6)

=> X²+16 -8X -(X²+36 -12X)

=> X²+16 -8X -X²-36+12X

=> 12X-8X-36+16

=> 4X - 20= 0

=> X = 20/4

=> X= 5

HOPE IT WILL HELP YOU... :-)