Question

find zero of polynomial when f(x)=x square​

Answer 1

Answer:

the zero of this fucyion is 0

x=0

hopw it helps

Answer 2

Step-by-step explanation:

We have,

f(x)=x

2

−2

=x

2

−(

2

)

2

=(x−

2

)(x+

2

)

The zeroes off(x) are given by f(x)=0

(x−

2

)(x+

2

)=0

(x−

2

)=0 or,(x+

2

)=0

x=

2

or x=−

2

Thus ,the zeroes of f(x) are α=

2

and β=−

2

Now,

Sum of the zeroes=α+β=

2

+(−

2

)

=0

and, −(

coefficient of x

2

coefficient of x

)=−(

1

0

)=0

Therefore sum of the zeroes=−(

coefficient of x

2

coefficient of x

)

Product of the zeroes=α×β=

2

×−

2

=−2

and,

coefficient of x

2

constant term

=

1

−2

=−2

Therefore, product of zeros =

coefficient of x

2

constant term