Find zero of qyadratic equation for f(u)=4usquare + 8u
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Hey
Here is your answer,
4u^2+8u=9
4u(u+2)=9
(4u)(u+2)=0
4u=0
u=0
u+2=0
u=-2
Hope it helps you!
Here is your answer,
4u^2+8u=9
4u(u+2)=9
(4u)(u+2)=0
4u=0
u=0
u+2=0
u=-2
Hope it helps you!
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