find zero of s²-5s +4
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Answer:
1,4
Step-by-step explanation:
s^2 -4s-s+4
s(s-4)-1(s-4)
(take s common from s^2 and 4s and also take 1 common from s and 4)
(s-1) (s-4)
So zeroes are:
s-1=0 => s=1
s-4=0 => s=4
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