Question

find zero of $3 x^{2} -10x+7$

Answer 1

3x^2-10x+7
=3x^2-3x-7x+7=0
3x(x-1)-7(x-1)=0
(x-1)(3x-7)=0
x-1=0                3x-7=0
x=1                    x=7/3
thats it

Answer 2

To find zero, equate it to 0 and solve:

$3 x^{2} -10x+7=0 \\ \\ 3 x^{2} -3x-7x+7=0 \\ \\ 3x(x-1)-7(x-1)=0 \\ \\ (x-1)(3x-7)=0$

$x=1$ and $x= \frac{7}{3}$