Question

find zero of the following polynomial.... a) 2x^2-7x-15​

Answer 1

Answer:

x = 5 or x = ( $-\dfrac{3}{2}$ )  Decimal value  - 1.5

Step-by-step explanation:

Given :

$\large p(x)=2x^2-7x-15$

We have to find zeroes of polynomial x.

By splitting mid term method we get

$\large p(x)=2x^2-7x-15\\\\\\\large p(x)=2x^2-10x+3x-15\\\\\\\large p(x)=2x(x-5)+3(x-5)\\\\\\\large p(x)=(x-5)(2x+3)$

For zeroes we have

x - 5 = 0

x = 5

or

2 x + 3 = 0

2 x = -3

x = $-\dfrac{3}{2}$

Thus we get x = 5 or x = - 1.5 ( - 3 / 2)