Question

find zero of the following polynomial..... a) x^2+9x+18​

Answer 1

Answer:

x = -6 or x = -3.

Step-by-step explanation:

Given :

$\large p(x)=x^2+9x+18$

We have to find zeroes of p ( x ).

By splitting mid term method we get

$\large p(x)=x^2+9x+18\\\\\\\large p(x)=x^2+6x+3x+18\\\\\\\large p(x)=x(x+6)+3(x+6)\\\\\\\large p(x)=(x+6)(x+3)$

For zeroes we have

x + 6 = 0

x = - 6

or

x  + 3 = 0

x = -3

Thus we get x = -6 or x = -3.

Answer 2

x² + 9x + 18

_________ [GIVEN POLYNOMIAL]

• We have to find the zeros of the above polynomial.

_____________________________

=> x² + 9x + 18 = 0

=> x² + 3x + 6x + 18 = 0

=> x(x + 3) +6(x + 3) = 0

=> (x + 6) (x + 3) = 0

• x + 6 = 0

=> x = - 6

• x + 3 = 0

=> x = - 3

____________________________

- 3 and - 6 are the zeros of the polynomial x² + 9x + 18

__________ [ANSWER]