Question

Find zero of the following polynomials
(i)p(x) = ax+ b.
(ii)p(x) = x2 -3x + 2​

Answer 1

Answer:

see attachment

Step-by-step explanation:

see attachment

Answer 2

Answer:

(i) $\frac{-b}{a}$

(ii) x = 1 , 2

Step-by-step explanation:

Given,

(i) p(x) = ax+b

(ii) p(x) = $x^{2} -3x+2$

(i) ax+b = 0

⇒ x = $\frac{-b}{a}$

(ii) $x^{2} -3x+2 = 0$

⇒$x^{2} -x-2x+2=0$

⇒$x(x-1)-2(x-1)=0$

⇒$(x-2)(x-1)=0$

⇒$(x-2) = 0 , (x-1) = 0$

⇒$x=2 , x=1$

Hope this answer helps you.