Question

find zero of the polynomial 10x²-x+30​

Answer 1

All zeroes are 1, -4 & -1/4

Step-by-step explanation:

We are given with one Zero of polynomial 3x³ + 10x² - 9x - 4 let say, p(x) = 3x³ + 10x² - 9x - 4 & zero = 1

Thus, one factor of p(x) = (x-1)

We get another factor of p(x) by dividing it with x - 1

On division, quotient we get is 3x² + 13x + 4

p(x)=(x-1)(3x² + 13x + 4)

= (x - 1) (3x² + 12x + x + 4 ) = ( x − 1 ) [ 3x(x + 4) + (x + 4) ] = ( x − 1)(x + 4 ) (3x + 1)

For zeroes put p(x) = 0

(x-1)(x+4) (3x + 1) = 0 x + 4 = 0 & 3x + 1 = 0

x = -4 & x = -1/4

Therefore, All zeroes are 1, -4 & -1/4