Question

Find zero of the polynomial 35x^2-9x-18

Answer 1

Zeros Of A Polynomial

Given:-

35x² - 9x - 18

To Find:-

Zeros Of The Polynomial

Solution:-

Let us find the zeros of the given polynomial by quadratic formula.

Comparing it with the general equation ax² + bx + c

a = 35

b = -9

c = -18

We know that,

D = b² - 4ac

Substitute the values in the above discriminant formula.

D = (-9)² - 4 × 35 × (-18)

D = 81 + 2520

D = 2601

√D= 51

x = (- b ± √D)/2a

x = (9 ± 51)/70

• x = (9 + 51)/70

x = 60/70

x = 6/7

and

• x = (9 - 51)/70

x = - 42/70

x = - 21/35

x = - 3/5

=> The zeros of the given polynomial are 6/7 and - 3/5.

Answer 2

Given :  35x² - 9x + 18

To find :  zeroes of the polynomial

Solution:

35x² - 9x + 18

= 35x² - 30x  + 21x - 18

= 5x(7x - 6) + 3(7x - 6)

= (5x + 3)((7x - 6)

(5x + 3)((7x - 6)  = 0

=> x = -3/5  or  x =  6/7

Zeroes of polynomial are

-3/5  & 6/7

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