Find zero of the polynomial 35x^2-9x-18
Answers
Zeros Of A Polynomial
Given:-
35x² - 9x - 18
To Find:-
Zeros Of The Polynomial
Solution:-
Let us find the zeros of the given polynomial by quadratic formula.
Comparing it with the general equation ax² + bx + c
a = 35
b = -9
c = -18
We know that,
D = b² - 4ac
Substitute the values in the above discriminant formula.
D = (-9)² - 4 × 35 × (-18)
D = 81 + 2520
D = 2601
√D= 51
x = (- b ± √D)/2a
x = (9 ± 51)/70
- x = (9 + 51)/70
x = 60/70
x = 6/7
and
- x = (9 - 51)/70
x = - 42/70
x = - 21/35
x = - 3/5
=> The zeros of the given polynomial are 6/7 and - 3/5.
Given : 35x² - 9x + 18
To find : zeroes of the polynomial
Solution:
35x² - 9x + 18
= 35x² - 30x + 21x - 18
= 5x(7x - 6) + 3(7x - 6)
= (5x + 3)((7x - 6)
(5x + 3)((7x - 6) = 0
=> x = -3/5 or x = 6/7
Zeroes of polynomial are
-3/5 & 6/7
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