Question

Find zero of the polynomial
P(x) = 3ax + 2a^2

Answer 1

Answer:-2/3a^3

Step-by-step explanation:

3ax+2a^2=0

3x+2=0/a^3

x=2/3a^3

Answer 2

Answer:

x = -2a^2/3a

Step-by-step explanation:

p(x) = 3ax + 2a^2

p(-2a^2/3a) = 3a × -2a^2/3a + 2a^2

= -2a^2 + 2a^2

= 0