Question

Find zero of the polynomial: PX equals to x minus 2 whole square minus x + 2 whole square

Answer 1

Step-by-step explanation:

p(x)=(x-2)²-(x+2)²

This is in the form of a²-b²

p(x)=(x-2+x+2)(x-2-(x+2))

p(x)=2x(x-2-x-2)

p(x)=2x(-4)

p(x)=-8x

p(x)=0

-8x=0

x=0

x=0 is the zero of the polynomial p(x)

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Answer:

The zero of the polynomial is 0.

Step-by-step explanation:

Given polynomial p(x) =

………………equation 1

Apply the formula

Here in the above equation 1

a= (x-2)    

b=(x+2)    

By substituting the values of a and b in the equation 1

We get= [(x-2) +(x+2)] [(x-2) -(x+2)]=0

[In the above step while simplifying we have to be careful with the + and – signs]

Simplify the above equation

(x-2+x+2)(x-2-x-2)=0

(2x)(-4)=0

-8x=0

x=0

Therefore p(x)= is 0

Answer 2

The zero of the polynomial is 0.

Step-by-step explanation:

The given polynomial is

$P(x)=(x-2)^2-(x+2)^2$

Perfect square trinomials.

$(a+b)^2=a^2+2ab+b^2$

$(a-b)^2=a^2-2ab+b^2$

Using these formulas we get

$P(x)=x^2-4x+4-(x^2+4x+4)$

$P(x)=x^2-4x+4-x^2-4x-4$

Combine like terms.

$P(x)=(x^2-x^2)+(-4x-4x)+(4-4)$

$P(x)=-8x$

Equate P(x)=0 to find the zeroes.

$-8x=0$

Divide both sides by -8.

$x=0$

Therefore, the zero of the polynomial is 0.

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