Question

Find zero of the quadratic polynomial 6x^2-3

Answer 1

$6x {}^{2} - 3 = 0 \\ = > 6x {}^{2} = 3 \\ = > x {}^{2} = \frac{3}{6} \\ = > x {}^{2} = \frac{1}{2 } \\ = > x = \sqrt{ \frac{1}{2} }$

I hope that helps you

Answer 2

Answer:

The answer is $\sqrt{ \frac{1}{2} }$

Step-by-step explanation:

$6x {}^{2} - 3 \\ 6x {}^{2} = 3 \\ x { }^{2} = \frac{3}{6} \\ x = \sqrt{ \frac{1}{2} }$

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