Question

Find zero of the quadratic polynomial 6x^2-3

Answer 1

Answer:

1/√2,-1/√2

Step-by-step explanation:

6x²-3

3(2x²-1)

3[(√2x)²-(1)²]

3[(√2x+1)(√2x-1)]

so, alpha=1/√2

beta= -1√2