Question

find zero of the quadratic polynomial 8x²-21-22x and verify the relationship between zeroes and co-efficient of polynomial

Answer 1

refer the attachment...
so here it is
pls. mark me as the brainliest pls.

Answer 2

hiiiiiii friends............
here is your answer............

............ hope it help you......
we have...
8x^2-21-22x,so
8x^²-22x-21
factorization
8x^²-(28-6)x-21
8x^²-28x+6x-21
4x(2x-7)+3(2x-7)
(2x-7) (4x+3)

value of 8x^2-22x-21 is zero when (2x-7)=0or
(4x+3)=0 I. e when X=7/2 or X=-3/4.... therefore, the zeroes of 8x^2-22x-21 are 7/2 and -3/4

sum of zeroes=7/2+-3/4=11/4=-x/x^²=22/8=11/4

product of zeroes=7/2×-3/4=-21/8=c/x^²=-21/8


by aryan