Question

find zero's of the given polynomial-
f(x) = x^2 -3x + 2

Answer 1

Explanation:

$x {}^{2} - 3x + 2$

$= x { }^{2} - x - 2x + 2$

$= x(x - 1) - 2(x - 1)$

$= (x - 1)(x - 2)$

Therefore, x = 1 or x = 2.

Answer: x = 1, x = 2

Answer 2

Answer:

x²-3x+2

= x²-(2+1)x+2

= x²-2x-1x+2

= x(x-2)-1(x-2)

= (x-2)(x-1)

zeroes of polynomial

either (x-2) = 0 OR (x-1) = 0

i.e., x = 2 or 1

so, the zeroes are 1 or 2...

Explanation:

hope it helps you

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