Question

Find zeroes and verify the realtionship between the zeroes and coefficients x2-2x-8

Answer 1

Answer:

hi

your answer is here !

Step-by-step explanation:

Heya !!!

P(X) => X²-2X-8

=> X²-4X+2X-8

=> X(X-4) +2( X-4)

=> (X-4) (X+2) = 0

=> (X-4) = 0 OR (X+2) = 0

=> X = 4 OR X = -2

4 and -2 are the two zeroes of the polynomial X²-2X-8.

RELATIONSHIP BETWEEN THE ZEROES AND COEFFICIENT.

Sum of zeroes = Alpha + Beta = 4 + (-2) = 4-2 = 2/1 = Coefficient of X/Coefficient of X².

And,

Product of zeroes = Alpha × Beta = 4 × -2 = -8/1 = Constant term/Coefficient of X².

HOPE IT WILL HELP YOU...... :-)

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Answer 2

Step-by-step explanation:

Step-by-step explanation:Let p(x)=x²-2x-8

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4)

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2we observe that,

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2we observe that,Sum of its zeroes

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2we observe that,Sum of its zeroes=4+(-2)=2

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2we observe that,Sum of its zeroes=4+(-2)=2=-(-2)/1

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2we observe that,Sum of its zeroes=4+(-2)=2=-(-2)/1=-(coefficient of x)/coefficient of x²

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2we observe that,Sum of its zeroes=4+(-2)=2=-(-2)/1=-(coefficient of x)/coefficient of x²Product of its zeroes

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2we observe that,Sum of its zeroes=4+(-2)=2=-(-2)/1=-(coefficient of x)/coefficient of x²Product of its zeroes=4×(-2)=8=-8/1

Step-by-step explanation:Let p(x)=x²-2x-8By the method of splitting the middle term,x²-2x-8=x²-4x+2x-8 =x(x-4)+2(x-4) =(x-4)(x+2)For the zero of p(x),put p(x)=0=> (x-4)(x+2)=0=>x-4=0 or x+2=0 => x=4 or x=-2=>. x=4,-2so,the zeroes of p(x) are 4&-2we observe that,Sum of its zeroes=4+(-2)=2=-(-2)/1=-(coefficient of x)/coefficient of x²Product of its zeroes=4×(-2)=8=-8/1=coefficient term/coefficient of x²

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