Question

find Zeroes and verify the relation
between zeroes and coefficient
8x^ - 4

Answer 1

Answer:

32

Step-by-step explanation:

Answer 2

Question:

find Zeroes and verify the relation

between zeroes and coefficient

8x²- 4.

Answer:

$\: \: \tt x =\pm \frac{1}{ \sqrt{2} } .$

Step-by-step explanation:

We have Equation,

$\: \: \: \: \: \: \tt \: {8x}^{2} - 4 = 0. \\ \leadsto \: \: \tt {x}^{2} = \frac{4}{8} \\ \leadsto \tt \: x = \sqrt{ \frac{1}{2} } \\ \leadsto x = \pm\frac{1}{ \sqrt{2}}$

Let's,

$\alpha = \frac{1}{ \sqrt{2} } \: \: and \: \: \beta = - \frac{1}{ \sqrt{2} } \\ \\ \leadsto \alpha + \beta = \frac{ - b}{a} \\ \leadsto \frac{1}{ \sqrt{2} } - \frac{1}{ \sqrt{2} } = 0. \\ \leadsto0 = 0. \\ \\ \leadsto \alpha \times \beta = \frac{c}{a} \\ \leadsto\frac{1}{ \sqrt{2} } - \frac{1}{ \sqrt{2} } = - \frac{1}{2} \\ \leadsto - \frac{1}{2} = - \frac{1}{2}$