find zeroes and verify the relationship p(x)=x^2+7x+12
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Answered by
1
Heya !!!
P(X) = X²+7X + 12
=> X² +7X + 12
=> X² + 4X +3X + 12
=> X ( X +4) + 3( X +4)
=> ( X +4) ( X +3) = 0
=> ( X+4) = 0 OR ( X+3) = 0
=> X = -4 OR X = -3
Let Alpha = -4 and Beta = -3
Relationship between the zeroes and Coefficient.
Sum of zeroes = Alpha + Beta = - 4 - 3 = -7 = - (Coefficient of X)/(Coefficient of X²).
And,
Product of zeroes = Alpha × Beta = -4 × -3 = 12/1 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU..... :-)
P(X) = X²+7X + 12
=> X² +7X + 12
=> X² + 4X +3X + 12
=> X ( X +4) + 3( X +4)
=> ( X +4) ( X +3) = 0
=> ( X+4) = 0 OR ( X+3) = 0
=> X = -4 OR X = -3
Let Alpha = -4 and Beta = -3
Relationship between the zeroes and Coefficient.
Sum of zeroes = Alpha + Beta = - 4 - 3 = -7 = - (Coefficient of X)/(Coefficient of X²).
And,
Product of zeroes = Alpha × Beta = -4 × -3 = 12/1 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU..... :-)
Anonymous:
Saniya please check your answer.....!! :-)
Saniya ab = c/a = 12/2 = 6 { Constant }
Nope Saniya
Wait wait
I am sorry ! Yes you are right coefficient of X should be 1.
Answered by
1
here is your answer by Sujeet,
x²+7x+12
x²+3x+4x+12
x(x+3)+4(x+3)
therefore
x+4=O
x=-4
again,
x+3=0
x=-3
relationship between zeroes,
a+b=-b/a=-7/1
ab=c/a=12/1=12
that's all
Sujeet...
x²+7x+12
x²+3x+4x+12
x(x+3)+4(x+3)
therefore
x+4=O
x=-4
again,
x+3=0
x=-3
relationship between zeroes,
a+b=-b/a=-7/1
ab=c/a=12/1=12
that's all
Sujeet...
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