Find zeroes for 4u^2+8u and find relation ship b/w zeroes and co-efficients
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4u^2+8u=0 can also be written as 4u^2+8u+0. Where c is zero.
On factorisation we get 4u(u+2)=0
Thus the zeroes are 0,-2.
Comparing this equation to ax^2+bx+c we get a=4,b=8,c=0
Now, sum of zeroes=-b/a=-8/4=-2+0
Also, the product of zeroes is c/a=0/4=-2*0=0
We can verify this for all quadratic polynomials hence we have found the relationship between coefficients and zeroes of a quadratic polynomial
On factorisation we get 4u(u+2)=0
Thus the zeroes are 0,-2.
Comparing this equation to ax^2+bx+c we get a=4,b=8,c=0
Now, sum of zeroes=-b/a=-8/4=-2+0
Also, the product of zeroes is c/a=0/4=-2*0=0
We can verify this for all quadratic polynomials hence we have found the relationship between coefficients and zeroes of a quadratic polynomial
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