Question

Find zeroes of
(√3) x^2 - 8x + 4 √3​

Answer 1

√3x² – 8x + 4√3 = 0

√3x² – 6x – 2x + 4√3 = 0

√3x ( x – 2√3 ) – 2 ( x – 2√3 ) = 0

( x – 2√3 ) ( √3x – 2 ) = 0

x – 2√3 = 0

x = 2√3

√3x – 2 = 0

√3x = 2

x = 2 / √3

after rationalisation

x = 2√3 / 3