Question

Find zeroes of 3y^2-6y+4

Answer 1

3y2-6y+4=0

Two solutions were found :

y =(6-√84)/-6=1+1/3√ 21 = 0.528

y =(6+√84)/-6=1-1/3√ 21 = -2.528

Step by step solution :

Step 1 :

Equation at the end of step 1 :

((0 - 3y2) - 6y) + 4 = 0

Step 2 :

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

-3y2 - 6y + 4 = -1 • (3y2 + 6y - 4)

Trying to factor by splitting the middle term

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