find zeroes of 4xsquare+24x+36
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Answered by
1
=4x²+24x+36
=4(x²+6x+9)
=x²+6x+9
=x²+3x+3x+9
=x(x+3)+3(x+3)
=(x+3)(x+3)
x=-3
=4(x²+6x+9)
=x²+6x+9
=x²+3x+3x+9
=x(x+3)+3(x+3)
=(x+3)(x+3)
x=-3
Answered by
0
solution:
The given Polynomial is 4x^2+24x+36
=> 4 (x^2+ 6x+9)=0
=> x^2+ 6x+9
=> x^2+3x+3x+9
=> x(x+3)+ 3(x+3)
=> (x+3) (x+3)
either x+3=0 or x+3=0
=> x+3=0 or x+3=0
=> x=-3 or x=-3
________________
hope it helps⤴⤴⤴
☺
The given Polynomial is 4x^2+24x+36
=> 4 (x^2+ 6x+9)=0
=> x^2+ 6x+9
=> x^2+3x+3x+9
=> x(x+3)+ 3(x+3)
=> (x+3) (x+3)
either x+3=0 or x+3=0
=> x+3=0 or x+3=0
=> x=-3 or x=-3
________________
hope it helps⤴⤴⤴
☺
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