Question

find zeroes of 6x^2-√2x-2=0​

Answer 1

Answer:

Step-by-step explanation:

6x²-√2x-2 =0

D = b²-4ac = √2² -4×6×-2 = 2 + 48 = 50

So x = -b +√D/2a =√2 + √50/2×6 = √2 +5√2 /12 [√50 = √5×5×2 = 5√2]

= 1/√2

Other root x = -b -√D/2a = √2 - √50/2×6 = √2 -5√2 /12

= √2/3

So both roots or zeroes are 1/√2 and √2/3