Question

Find zeroes of f(x)=x³-5x²-2x+24 if product of 2 zeroes is 12.

Answer 1

ask any doub if you have

Answer 2

Hey!!!

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We have

f(x) = x³ - 5x² - 2x + 24

$let \: the \: zeros \: be \: \alpha \beta \: and \: \gamma$


Thus


$\alpha \beta = 12(given)$

We know

$\alpha \beta \gamma = \frac{ - d}{a}$

Replacing Value

$= > 12 \gamma = - 24$

Thus

$= > \gamma = - 2$

Thus the third zero is -2.

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