Question

Find zeroes of P(x) = 3x^2+8x-3​

Answer 1

Given:

• A polynomial is given.
• The polynomial is p(x)=3x²+8x-3.

To Find:

• The zeroes of the given polynomial.

Answer:

To find the zeroes of the polynomial will equate it with 0.

=> 3x²+8x-3=0

=> 3x² +9x-x-3=0

=>3x(x+3)-1(x+3)=0

=>(3x-1)(x+3)=0

=> x = 1/3 and -3.

Hence the required zeroes are ⅓ and -3.

Answer 2

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☞︎︎︎ 3x^2 + 8x - 3

3x^2 + 9x - x - 3

3x ( x + 3 ) - 1 (x + 3 )

➪ ( x + 3 ) ( 3x - 1 ) ✓