Question

Find zeroes of P(x)=3x^2-x-4

Answer 1

Answer:

$x=(-1),\frac{4}{3}$

Step-by-step explanation:

P(x)=3x²-x-4=0

3x²-4x+3x-4=0

x(3x-4)+1(3x-4)=0

(x+1)(3x-4)=0

x=(-1), $\frac{4}{3}$