Math, asked by iisisisjsjs, 1 year ago

Find zeroes of p (x) = 3x2 - 12

Answers

Answered by arshbbcommander

0

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To find zeros of p(x) = 3x² - 12

Let p(x)=0

3x² - 12=0

3x² = 12

x² = 12/3

x² = 4

x= 2 or x=-2

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...Hope it helps....

Answered by Ashi03

5

Step-by-step explanation:

To find zeros of p(x) = 3x² - 12

Let p(x)=0

3x^2 - 12=0

3x^2= 12

x^2 = 12/3

x^2 = 4

x= 2 or x=-2

Hope it helps!

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