Question

find zeroes of p( x ) = 6x² - 3.
And also verify the relationship b/w them ..
Please answer
Will mark Brainliest​

Answer 1

Answer:

let p(x) =0

so 6x^2-3=0

6x^2=3

x^2=3/6

x=√1/2

Answer 2

Answer:

Step-by-step explanation:

6x²-3=0

3(2x²-1)=0

2x²-1=0

2x²=1

x²=1/2

x=±√1/2

x=±√2/2

this means there two answers to this question which are:+√2/2and -√2/2