Question

Find zeroes of P(x) = t^2-16​

Answer 1

Answer:

here is u r ans ..

Step-by-step explanation:

.. t²-16= o

t = +-(4) .

Answer 2

Answer:

t=±4

Step-by-step explanation:

First method

t²-16=0

t²=16

t=±4

Second Method

t²-16=0

(t)²-(4)²=0

(t+4)(t-4)=0

t=±4

Remember:

a²-b²= (a+b)(a-b)