Find Zeroes of p(x)= x(x+2)(x+3)
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Zeroes of p(x)= x(x+2)(x+3) are 0, -2 and -3.
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Answer:
Value of x is 0,-2, -3
Step-by-step explanation:
P(x) = 0
(x) =0 ; x+2 ; x+3=0
x=0; x= -2 ; x= - 3
value of x is 0,-2,-3
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