Question

find zeroes of p(x)=x2-5 and verify the relation​

Answer 1

Answer:

Given polynomial is x2−5.

Let the zeros be α,β. ( α>β)

x2−5=0⇒x2=5⇒x=±5.

α=5 ,β=−5.

So, α+β=0,αβ=−5.

The coefficient of x is zero ⇒α+β=0.

Constant = αβ=−5.

Step-by-step explanation:

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