Question

Find zeroes of polynomial 2√3 x^2 + 52 + √3​

Answer 1

Answer:

52+root 3

Step-by-step explanation:

52+ root 3 is the correct answer

Answer 2

Answer:

We have: f(x)=x2+3x−10 =x2+5x−2x−10 =x(x+5)−2(x+5) =(x−2)(x+5) ∴f(x)=0=>(x−2)(x+5)=0 =>x−2=0 or x+5=0 =>x=2 or x=−5 So, the zeroes of f(x)are 2 and−5. Sum of the zeroes = 2+(−5)= −3=

−3

1

=

−(coefficient of x)

(coefficient of x2)

Product of the zeroes= 2× (−5) = −10 =

−10

1

=

constant term

(coefficient of x2)