Question

find zeroes of polynomial 6x³-7x²-11x+12, if x-1 is a factor of the polynomial​

Answer 1

Answer:

x -1

x = 1

6*1^3 - 7*1^2 - 11*1 + 12

6 - 7 - 11 + 12

6 - 18 + 12

6 - 6

0

Answer 2

x-1=0

x=1

p(1)=6(1)³-7(1)²-11×(1)+12

= -6-7-11+12

=6+6

=0